The temperature that the sample of a gas will occupy at a volume of 502 Ml is 293.7 K
calculation
This is calculated using the Charles law formula
that is V1/T1 =V2/T2
where, V1=482Ml
T1= 282 K
V2 = 502 ml
T2 = ?
make T2 the subject of the formula
T2=V2T1/V1
T2= (502 ml x282 k) /482 ml=293.7 k
