Write x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers.
A). (x − 4)2 = 3
B). (x − 3)2 = 2
C). (x − 2)2 = 1
D). (x − 1)2 = 4

Question

11-05-2017
Mathematics

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Write x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers.
A). (x − 4)2 = 3
B). (x − 3)2 = 2
C). (x − 2)2 = 1
D). (x − 1)2 = 4

Respuesta :

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mreijepatmat mreijepatmat · Answer 1 · 2017-05-13T02:47:41+02:00

x² − 6x + 7 = 0

Let's complete the square [x²-6x+(??)²] -(??)² +7 = 0

As you noticed we have added the unknown square & also subtract the same so that not to change the equation

The question now is to calculate this square (??)²

We know that the middle term (6x) is twice the square root of the 1st times the square root of the 2nd, That is 6x=2x (multiply) √(??)²

6x = 2x?? & ??=6x/2x===> ?? =3 & (??)² =9

Hence plug (??)² into the equation above:

x² - 6x + 9 - 9 +7 =0

(x²-6x+9) -9 + 7 =0

(x-3)² -2 =0 ====> (x-3)² = 2 (that is B)

agentaustin agentaustin · Answer 2 · 2017-05-19T20:56:26+02:00

agentaustin agentaustin

19-05-2017

the best answer is B

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Write x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers. A). (x − 4)2 = 3 B). (x − 3)2 = 2 C). (x − 2)2 = 1 D). (x − 1)2 = 4

Respuesta :

Otras preguntas

Write x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers.
A). (x − 4)2 = 3
B). (x − 3)2 = 2
C). (x − 2)2 = 1
D). (x − 1)2 = 4