Respuesta :

sharmaenderp
We need to locate the median of the set given. So, it's important for us to arrange the data in increasing order first. Hence we have

10.5 11 11.5 14.5 14.5 17 17 18 19 
 
Now that we have the value of the median for  the entire set, we now separate the group into a group below and above the median as shown below.

(10.5 11 11.5 14.5) 14.5 (17 17 18 19)

Now, let's find the median for the subgroup. For the lower boundary, the media is (11 + 11.5)/2 = 11.25. As for the upper boundary, we have (17 + 18)/2 = 17.5. 

The interquartile range (IQR) is the difference between the two medians of the lower and upper boundary. Hence, the IQR = 17.5 - 11.25 = 6.25.

Answer: 6.25

By using median we got IQR of 11, 11.5, 10.5, 17, 14.5, 14.5, 18, 17, 19  is 6,25

What is IQR?

The interquartile range (IQR) is the difference between the two medians of the lower and upper boundary.

Given data is

11, 11.5, 10.5, 17, 14.5, 14.5, 18, 17, 19

Arranging data in ascending order

10.5, 11 ,11.5, 14.5, 14.5, 17, 17 ,18 ,19

Total number of terms = 9

Hence median = [tex][\frac{(9+1)}{2} ]^{th}[/tex] term

Hence median = [tex]5^{th}[/tex] term =14.5

now separate the group into a group below and above

(10.5 11 11.5 14.5) 14.5 (17 17 18 19)

Now, we can  the median for the subgroup as

For the lower boundary, the median is (11 + 11.5)/2 = 11.25.

And for the upper boundary, median =(17 + 18)/2 = 17.5.

Now we can calculate IQR as

IQR = 17.5 - 11.25 = 6.25.

By using median we got IQR of 11, 11.5, 10.5, 17, 14.5, 14.5, 18, 17, 19  is 6,25

To learn more about median visit : https://brainly.com/question/19243813

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