For any probability the formula is [tex]P_{desired}=\frac{desired}{total}[/tex]. In this case we have 4 desired outcomes (the odds, 1, 3 and 5, and also 6) out of 6 total sides, so our probability [tex]P_{oddor6} =\frac{odd or 6}{total sides}=\frac{4}{6} = \frac{2}{3}[/tex].
Mutually exclusive means the events cant occur at the same time. In our case it is not possible to roll both a 6 and an odd number at the same time since 6 is even. Therefore the events ARE mutually exclusive.
Combine the two parts and C is the correct answer.
