Answer: 3248.0 kPa of pressure will be exerted by 10 moles of hydrogen gas in a 7.5 L cylinder at 20°C.
Explanation:
Using ideal gas equation:
PV = nRT
[tex]P=\frac{nRT}{V}[/tex]
P= pressure = ?
V= volume = [tex]7.5L[/tex]
n = no of moles = 10 moles
R= gas constant =0.0821 kPaL\molK
T= temperature = [tex]20^0C=20+273=293K[/tex]
[tex]P=\frac{10\times 8.314kPaatm\molK\times 293K}{7.5L}[/tex]
[tex]P=3248.0kPa[/tex]
Thus pressure exerted is 3248.0 kPa
