Respuesta :
Given:
Aluminum Phosphate (AlPO4 (s))
When dissolved in water, it becomes:
Balanced Chemical Equation:
AlPO4 (s) + 3H2O (l) ===> H3PO4 (aq) + Al (OH) 3 (aq)
AlPO4 + 3 H + ===> Al 3+ (aq) + PO4 3- (aq)
Aluminum Phosphate (AlPO4 (s))
When dissolved in water, it becomes:
Balanced Chemical Equation:
AlPO4 (s) + 3H2O (l) ===> H3PO4 (aq) + Al (OH) 3 (aq)
AlPO4 + 3 H + ===> Al 3+ (aq) + PO4 3- (aq)
Answer:
[tex] AlPO_4(s) + H_3O^+(aq) \longrightarrow H_2O(l) + HPO_4^{-2}(aq) +Al^{+3}(aq)[/tex]
Explanation:
Hi, the aluminum phosphate will dissociate when mixed in water:
[tex]AlPO_4 (s) \longrightarrow Al^{+3} (aq) + PO_4^{-3}(aq)[/tex]
or if you prefer:
[tex]AlPO_4 (s) + 3 H_2O (l) \longrightarrow Al(OH)_3(aq) + H_3PO_4(aq)[/tex]
Given that the solution is acid, the phosphate ([tex]PO_4^{-3}[/tex]) will react with the [tex]H_3O^+[/tex] because of the phosphate's basic power:
[tex] PO_4^{-3}(aq) + H_3O^+(aq) \longrightarrow H_2O(l) + HPO_4^{-2}(aq)[/tex]
The net ionic equation:
[tex] AlPO_4(s) + H_3O^+(aq) \longrightarrow H_2O(l) + HPO_4^{-2}(aq) +Al^{+3}(aq)[/tex]