The population of a city 5 years ago was 36,000 people. By this year, the city's population had grown to 43,800 people. Assume the population has grown linearly and will continue to grow this way. What will the population of the city be 5 years from now? Assume the population has grown exponentially and will continue to grow this way. What will be the population of the city 5 years from now?

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irspow
Assuming linear growth means:

y=mx+b,

m=(y2-y1)/(x2-x1)=(43800-36000)/5

m=1560

y=1560x+b, so y increases by 1560 for every year elapsed...

43800+1560(5)=51600 people five years from now...

Now for the exponential case:

43800/36000=ar^5/ar^0

73/60=r^5

r=(73/60)^(1/5)

43800(73/60)^(1/5)^(5)

43800(73/60)

53290 people five years from now...


Answer:

The Correct Answer:

53290 people five years from now

Step-by-step explanation:

Assuming linear growth means:

y=mx+b,

m=(y2-y1)/(x2-x1)=(43800-36000)/5

m=1560

y=1560x+b, so y increases by 1560 for every year elapsed...

43800+1560(5)=51600 people five years from now...

Now for the exponential case:

43800/36000=ar^5/ar^0

73/60=r^5

r=(73/60)^(1/5)

43800(73/60)^(1/5)^(5)

43800(73/60)

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