Find the solution of the initial value problem y'' - 2y' -3y = 21te^2t , y(0)=4 y'(0)=0. Please show all steps.

Respuesta :

Answer:

[tex]y=-\frac{3}{4}e^{3t}+\frac{1}{12}e^{-t}-7te^{2t}+\frac{14}{3}e^{2t}[/tex]

Step-by-step explanation:

Refer to the attached images. Please follow along carefully.

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