A 60-V potential different is applied across a parallel combination of a 10-ohm and 20-ohm resistor. What is the current in the 10-ohm resistor? Show your work.

Beats are two tones of slightly different frequency sounded together. When two slightly mismatched forks are sounded together, beats are heard. Beating in waves is the result of "superposing" - sort of adding together - two waves of different but similar frequencies - eg 50 Hz and 51Hz. The waves go in and out of phase as a sort of continuous or running interference pattern. In the case of sound, you'd hear it as a continuous change in the sound intensity loud in phase, soft out of phase. An example is walking side by side to another person. Sometimes you two will be in the same step and other times you’ll be in different step. If you step 60 times in a minute and your friend takes 63 in that minute, your friend gains three steps per minute on you. This shows that you two will be in step three times per minute. This goes for forks and frequency as well. When one fork vibrates 242 times per second and the other 240 per second, they are in step twice each second. This results in 2 hertz beat frequency.

Lanuel Lanuel · Answer 2 · 2022-04-14T13:40:48+02:00

By applying Ohm's law, the current in the 10-ohm resistor is equal to 6 Amperes.

Given the following data:

Voltage = 60 Volts.

Resistor 1 = 10 Ohms.

Resistor 2 = 20 Ohms.

How to calculate the current.

In order to determine the amount of current that is flowing through the 10-Ohm resistor (Resistor 1), we would apply Ohm's law.

Mathematically, current is given by this formula in accordance with Ohm's law:

[tex]I = \frac{V}{R}[/tex]

Where:

I is the current.

R is the resistance.

V is the voltage.

Substituting the given parameters into the formula, we have;

I = 60/10

Current, I = 6 Amperes.

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