At a convention of monsters, 2/5 have no horns, 1/7 have one horn, 1/3 have two horns, and the remaining 26 have three or more horns. How many monsters are attending the convention?
if we take it that, the total amount is say hmmm "x" then one can say that [tex]\bf \begin{cases}
\cfrac{2}{5}x\impliedby &\textit{no horns}\\\\
\cfrac{1}{7}x\impliedby &\textit{one horn}\\\\
\cfrac{1}{3}x\impliedby &\textit{two horns}\\\\
26\impliedby &remaining
\end{cases}
\\\\\\
\textit{so the total is really }\quad \cfrac{2}{5}x+\cfrac{1}{7}x+\cfrac{1}{3}x+26[/tex]
add up the fractions of "x" and the constant of 26
