Answer:
The answer is [tex]3a^2y(a^2y^2-4ay+2)[/tex]
Step-by-step explanation:
Given the expression [tex]3a^4y^3-12a^3y^2+6a^2y[/tex]
We have to factor the above expression.
[tex]3a^4y^3-12a^3y^2+6a^2y[/tex]
Taking [tex]3a^2y[/tex] common from each term, we get
⇒ [tex]3a^2y(a^2y^2-4ay+2)[/tex]
Hence, the correct option is second.