Answer:
1/2log₂(a-1) -log₂(9)
Step-by-step explanation:
You want the expanded form of log₂(√(a-1)/9).
Rules of logarithms
The relevant rules of logarithms are ...
log(a^b) = b·log(a)
log(a/b) = log(a) -log(b)
The rules are applicable for any base.
Application
[tex]\log_2{\dfrac{\sqrt{a-1}}{9}}=\log_2{(\sqrt{a-1})}-\log_2{(9)}=\boxed{\dfrac{1}{2}\log_2{(a-1)}-\log_2{(9)}}[/tex]
