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A force F is applied in horizontal to a 10kg block. The block moves at a constant speed of 2 m/s across a horizontal surface. The coefficient of kinetic friction between the block and the surface is 0.5. The work done by the force F in 1.5 minutes is _____.

Respuesta :

The work done by the force F in 1.5 minutes is 9000J.

What is work done?

The product of the displacement and the component of the applied force of the object in the displacement direction is the work performed by a force. Work is accomplished when we push a block with some force; the body moves with some acceleration.

Work done formula will be given as, W = F x D.

fnxm (coeffient of friction) = f(friction)

⇒100x0.5=50

1.5min to seconds = 60x1.5= 90sec

Referring a velocity graph, since speed is constant therefore no acceleration, hence graph should look like rectangle v-2 on y axis, t=90 on x axis.

multiply like rectangle: 2x90=180

Therefore distance is 180m

W=FxD

W=50x180

W=9000J

Learn more about work done here:

https://brainly.com/question/25573309

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