Answer: Since p-value is greater than α = 0.05, we cannot reject the hypothesis H0, and we can conclude that it is insufficient evidence to conclude that the average difference is not zero.
Step-by-step explanation:
Step 1: We need to test the given hypothesis.
Step 2: Explanation
We can take x1- x2 to represent the difference between the jumping and relaxed times.
[tex]H0: u1 = u2\\H1: u1 \neq u2[/tex]
Step 3: Simplification
We need to find the mean and standard deviation of both samples.
[tex]u1 = 32.375, s1 = 9.620477\\u2 = 30.625, s2 = 8.331309[/tex]
The differences between the jumping and relaxed times are calculated:
[tex]5, 7, 2, 1, -2, 2, 2, -3[/tex]
The number of differences is ∑(8, i-1) = [tex](d_{i} - \alpha ) ^{2}[/tex] = 75.5
Standard deviation differences are:
[tex]\sqrt{\frac{75.5}{7} }[/tex] = 3.284
The standard error is SE = 1.161
Using this, we can find the value of the test statistic t:
[tex]t = \frac{u1 - u2}{SE}[/tex] = 1.507
Using this and the graph, we get that the p value is 0.17554.
Therefore, since p-value is greater than α = 0.05, we cannot reject the hypothesis H0, and we can conclude that it is insufficient evidence to conclude that the average difference is not zero.