in the air, it had an average speed of 161616 \text{m/s}m/sstart text, m, slash, s, end text. in the water, it had an average speed of 333 \text{m/s}m/sstart text, m, slash, s, end text before hitting the seabed. the total distance from the top of the cliff to the seabed is 127127127 meters, and the stone's entire fall took 121212 seconds.

Respuesta :

The time it takes for the stone to fall in the air is 7 seconds, and it takes 5 seconds for the stone to fall in the water in the seabed.

The average speed of the stone in air is shown here as 16 m/s.

The average speed of the stone in water is 3 meters per second.

The total distance from the top of the cliff to the seabed is 127 meters.

Total fall time = 12 seconds

Therefore

Let t1 represent the time spent by the stone in the air and

t2 = time spent by the stone in water

Now using the equations of motion we get :

Therefore, t₁ + t₂ = 12 s........(1)

16·t₁ + 3·t₂ = 127............(2)

From (1) t₁ = 12 - t₂

16×(12 - t₂) + 3×t₂ = 127

13t2 = 65 is the result.

and t2 equals 5 seconds

t1 = 12 - t2 = 12 - 5 = 7 sec

The time it takes for the stone to fall in the air is t1 = 7 seconds.

The time it takes for the stone to fall into the water is t2 = 5 seconds.

To learn more about seabed visit:

https://brainly.com/question/14322979

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