All fourth grade children on Long Island are given an examination on mathematical achievement. A random sample of 60 fourth graders are selected. Their examination results are summarized in the following stem-and-leaf plot. Find the sample upper quartile.4 6 6 6 88 01 7 7 7 7 7 8 33 445 6667777 8888889 00011111 2233333 4455 66777 8 8 8 8 899 9 001 9 223 45 9

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The sample upper quartile of the data set is 91 and the lower quartile is 67 for the students of the given examination.

The median and quartiles of a data set:

The data set's median, or 50th percentile, separates the bottom half from the higher half.

The first quartile is the median of the data set's first half.

The third quartile is the median of the data set's second half.

Because there are an even number of items 60, the median is the mean of the31st element elements, with the first half consisting of 30 elements ranging from 1 to 29, and the second half consisting of 12 elements ranging from 31 to  60.

The first quartile is the mean of the elements, 67 and 68, respectively, therefore Q1 = 60/4 =15th element =  67

The third quartile is defined as the mean of the sixth and seventh elements of the second half, hence Q3 = 3×60 / 4 = 91.

Hence the quartiles are at 67 and 91 respectively.

More can be learned about the quartiles at https://brainly.com/question/24329548

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