The Maryland Department of Transportation reported the following data on driving Speed (miles per hour, mph) and fuel efficiency or Mileage (miles per gallon, mpg), for ten mid-size automobiles: 1 23 4 5 6 7 89 10 Automobile Speed (mph 30 50 40 55 30 25 60 25 50 55 Mileage (mpg)2 25 25 2330 32 2 32625 a. Compute the sample bivariate correlation coefficient. b. Interpret the strength (magnitude) and sign (direction) of the sample bivariate correlation coefficient. Test whether the population bivariate correlation coefficient difers significantly from zero at α-0.01. c.State the null and alternative hypotheses associated with the test. d. What is the calculated value of the associated test statistic? e. What is the critical value of the associated test statistic? f.State your decision regarding the null hypothesis. g. State your conclusion (meaning, describe what the decision means in this problem)

Respuesta :

On solving the provided question we can say that - correlation coefficient of the question is r = [tex]\frac{S_{xy} }{\sqrt{S_{xx} S_{yy} } }[/tex] =  -0.91

What is correlation coefficient ?

The Pearson's correlation coefficient, also known as the Pearson's r, Pearson's product-moment correlation coefficient, bivariate correlation, or simply correlation coefficient, is a statistical indicator of the linear relationship between two sets of data.

[tex]S_{xx} =[/tex]∑[tex]x^2[/tex] - (∑x[tex])^2[/tex] /n = 19300- ((420)^2 /10)= 1660

[tex]S_{yy} =[/tex] ∑[tex]y^2[/tex] (∑y[tex])^2[/tex]/n = 7454- ((270)^2 /10) = 164

[tex]S_{xy} =[/tex]∑[tex](xy)^2[/tex]/n -475

The correlation coefficient is:

r = [tex]\frac{S_{xy} }{\sqrt{S_{xx} S_{yy} } }[/tex] =  -0.91

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