Two identical thin rods_ each of mass m and length L_ are joined at right angles to form an L-shaped object; This object is balanced on top of . sharp edge (Figure 1) If the object is displaced slightly; it oscillates: Part A Assume that the magnitude of the acceleration due to gravity iS g- Find W, the angular frequency of oscillation of the object Your answer for the angular frequency may contain the given variables mn and L as well as g- Figure 1 of 1 View Available Hint(s) AZd XOn Submit Previous Answers

Respuesta :

The angular frequency of oscillation of the object, ω is calculated to be= √3g / 2√ 2 L.

What is angular frequency of oscillation?

Number of oscillations per second of a particle executing simple harmonic motion is called angular frequency.

Given acceleration due to gravity is g,

=mg. L/2 {-2/√2* sinФ

When L- shaped object is slightly displaced by an angle, then

τ0 =mg. L/2 [(sin 45° - Ф) - (sin 45° + Ф)]

= 2 (mL²/3) α

= - (m*g*L Ф)/√3

α = -3g Ф/ 2√ 2 L

ω= √3g / 2√ 2 L

The angular frequency of oscillation of the object, ω= √3g / 2√ 2 L.

To know more about angular frequency of oscillation, refer

https://brainly.com/question/14932388

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