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coherent light from a sodium-vapor lamp is passed through a filter that blocks everything except for light of a single wavelength. it then falls on two slits separated by 0.470 mm . in the resulting interference pattern on a screen 2.24 m away, adjacent bright fringes are separated by 2.86 mm .What is the wavelength of the light that falls on the slits?
Im lost I don't know where to start.

Respuesta :

rafikiedu08

The light that hits the slits has a wavelength of [tex]5.692 *10^{-4} m[/tex]

Fringe separation = 2.90 mm = 0.0029 m

Slit separation = 0.420 mm = 0.00042 m

Screen distance from slits =2.14 mm = 0.00214 mm

Wavelength is given by the following relation;

Wavelength = Fringe Separation * Slit Separation / Distance from the slit to Screen

Thus,

Putting all the given values in the above formula,

We evaluate the wavelength in the following way, we get

Wavelength = [tex]\frac{0.0029 *0.00042}{0.00241}[/tex] = [tex]5.692 *10^{-4}[/tex] m

The light's wavelength when it hits the slits is [tex]5.692 *10^{-4}[/tex] m

To read more about wavelengths, visit https://brainly.com/question/1263539

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