Respuesta :
The standard enthalpy of formation of CO (g) is -114.15 kJ/mol (approx)
In thermodynamics, the standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements in their reference state, with all substances in their standard states.
S(s,rhombic) + 2CO (g) ===>>SO2(g) + 2 C (s,graphite)
The standard enthalpy change of the Reaction is given by:
ΔH°rxn = nΣ ΔHf°(products) - nΣ ΔHf° (reactants)
=> ΔHf°rxn = [1mole* ΔHf°SO2(g) + 2mole* ΔHf°C(s,graphite)] - [1mole * ΔHf°S(s, rhombic) + 2mole * ΔHf°CO(g) ]
=> -67.8 kJ = [1mole * (-296.1kJ/mol) + 2mole *( 0kJ/mol)] - [1mole* (0 kJ/mol) + 2mole * ΔHf°CO(g) ]
=> -67.8 kJ = -296.1 kJ - [ 2 mole * ΔHf° CO(g) ]
=> -67.8 kJ + 296.1 kJ = - 2 mole * ΔHf°CO(g)
=> 228.3 kJ = -2 mole * ΔHf°CO(g)
=>ΔHf° CO(g) = -114.15 kJ/mol
Learn more about Enthalpy here:
https://brainly.com/question/14047927
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