contestada

Place the following compounds in order of decreasing strength of intermolecular forces. I. CH3CH2CH2CH2CH2CH3 II. (CH3)3CCH3 IIL (CH3)3CCH2CH3 1) C) II >III> I 2) Identify the compound with the lowest boiling point. A) CH3CN B) CH3CHO C) CH3CH2CH3 D) (CH3)20 E) CH3OCH3 2) 3) Place the following substances in order of increasing vapor pressure at a given temperature SF6 SiH4 SF4 3) A) SiH4

Respuesta :

The following compounds in order of decreasing strength of intermolecular forces is as follows :

CH₃CH₂CH₂CH₂CH₂CH₃ > (CH₃)₃CCH₂CH₃ > (CH₃)₃CCH₃

1) The following compounds in order of decreasing strength of intermolecular forces is as follows : as the surface are decreases the intermolecular force decrease or as branching increases intermolecular forces decreases.

CH₃CH₂CH₂CH₂CH₂CH₃ > (CH₃)₃CCH₂CH₃ > (CH₃)₃CCH₃

2)  the compound CH₃CH₂CH₃ have the weaker van der wall forces and having the lowest boiling point.

3) the following substances in order of increasing vapor pressure at a given temperature is as follows :

SF₄  < SF₆   <  SiH₄  

SF₄ is the polar molecular and hs the lowest vapor pressure.

To learn more about intermolecular force here

https://brainly.com/question/14774937

#SPJ4

Otras preguntas