Respuesta :
The electric field at the center of the metal ball due only to the charges on the surrounding of the metal ball is 0 N/C.
The electric field is defined as the force acting on a positive test charge, per unit charge. units are thus N/C for the electric field. It is similar to the gravitational field on the surface of the Earth for a test mass mo
The electric field is a vector field. It has a magnitude and a direction. Another example is vector field is the wind distribution. Temperature distribution is an example of a scalar field.
Lines indicate the direction of F if a test charge is placed there, Field lines point away from positive charge, and toward negative charge, density of lines indicates the strength of the field.
Field lines cannot cross. If they did, there would be more than one possible direction for a particle to travel at a given point. The lines themselves have no meaning the field is present everywhere.
Since metal ball is considered as a solid sphere So the electric field inside metal ball is given by E=(p/3Eo)г
Where r is the distance from center and rho is charge density. Hence at the centre r=0
Then electric field =(p/3Eo)* 0 = 0 N/C
Hence electric field at the centre of the metal ball due to it's own charge only is 0 N/C.
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