2.67 L volume is occupied by 0.105 mol of helium gas at a pressure of 0.95 atm and a temperature of 295 k
Volume is defined as the space occupied within the boundaries of an object in three-dimensional space
Here given data is
Pressure = 0.95 atm
Temprature = 295 k
Number of mole of He gas = 0.105 mol
R = 0.0821 L.atm.K⁻¹mol⁻¹ = gas constant
We have to calculate volume = ?
So according to the ideal gas equation
PV = nRT
V = nRT/P
V = 0.105 mol × 0.0821 L.atm.K⁻¹mol⁻¹ × 295 k/0.95 atm
V = 2.67 L
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