If the concentration of NaCl is 7.61 m, when it begins to crystallize out of solution, then the Ksp is 57.91.
The dissociation reaction of NaCl is given as:
NaCl → Na⁺ + Cl⁻
7.61 7.61
The Ksp for the following is given as :
ksp = [Na⁺] [Cl⁻]
⇒ksp = 7.61 × 7.61
⇒ksp = 57.91
When a solid substance dissolves into an aqueous solution, it posses a equilibrium constant which is known as solubility product constant, Ksp. The solubility product constant Ksp increases with increase in temperature and with increase in the solubility.
Thus, If the concentration of NaCl is 7.61 m, when it begins to crystallize out of solution, then the ksp is 57.91 .
Learn more about Ksp of NaCl from the link given below.
https://brainly.com/question/27304688
#SPJ4
