contestada

A gas with a volume of 4. 0 l at a pressure of 205 kpa is allowed to expand to a volume of 12. 0 l. What is the pressure in the container if the temperature remains constant?.

Respuesta :

The pressure is 68.3 L.

P1V1 = P2V2

Here, P1 = initial pressure, given = 205 kPa

         V1 = initial volume, given = 4 L

         P2 = final pressure,  

         V2 = final volume, given = 12 L

Put, these values in P1V1 = P2V2

P2 = P1V1 / V2

P2 = 205 kPa × 4 L / 12 L

P2 = 68.3 L

Therefore, The pressure is 68.3 L.

Learn more about pressure here:- https://brainly.com/question/25736513

#SPJ4