Suppose that a department contains 10 men and 15 women. How many ways are there to form a committee with six members, if it must have the same number of men and women?.

Respuesta :

ayune

A department needs to choose six members consists of 3 women and 3 men from 10 men and 15 women. The number of ways it can be selected is 54,600.

If r persons need to be selected from total n members and the order does not matter, the number of ways it can be selected is calculated using the combination formula:

  ⁿCr = n! / [(n-r)! r!]

Data from the problem:

Total man = 10

Man to be chosen = 3

Total woman = 15

Woman to be chosen = 3

Hence,

The number of ways men can be selected =   ¹⁰C₃ = 10! /(3! 7!)

                                                                       = 120

The number of ways women can be selected =   ¹⁵C₃ = 15! /(3! 12!)

                                                                       = 455

The number of ways men and women selected:

= ¹⁰C₃ x  ¹⁵C₃

= 120 x 455 = 54,600 ways

Hence, the  number of ways the members can be selected =  54,600 ways.

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