Molar mass of the unknown gas= 39.09 g / mol
T= TIME
MW= MOLAR MASS
MW H₂ = 2
now, Apply graham law--
graham law states that rate of effusion of a gas is inversely proportional to square root of the molar mass of its particle.
Rate1/rate2 = √(MW2/MW1)
T2/T1 =√(MW2/MW1) (BECAUSE, VOLUME EQUAL)
(10.7/2.42)²= MW2/2
MW2=molar mass of the unknown gas = 2α×(10.7/2.42)²
=39.09 g / mol
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