The probability that the web site has fewer than 5 million visitors in a single day is 0.7293.
For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.
First, solve for the z-score using the formula below.
z-score = (x – μ) / σ
where x = individual data value = 5 million
μ = mean = 4.56 million
σ = standard deviation = 720,000
z-score = (5 million - 4.56 million) / 720,000
z-score = 440,000 / 720,000
z-score = 0.6111
Find the probability that corresponds to the z-score in the z-table. (see attached images)
z-score = 0.6111
Using interpolation of values,
probability = 0.7293
Learn more about probability here: brainly.com/question/26822684
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