question content area the average return for large-cap domestic stock funds over the three years 2009–2011 was 14.7%. assume the three-year returns were normally distributed across funds with a standard deviation of 4.7%. open spreadsheet what is the probability an individual large-cap domestic stock fund had a three-year return of at least 20% (to 4 decimals)? fill in the blank 2 what is the probability an individual large-cap domestic stock fund had a three-year return of 10% or less (to 4 decimals)? fill in the blank 3 how big does the return have to be to put a domestic stock fund in the top 10% for the three-year period (to 2 decimals)? fill in the blank 4 %

Respuesta :

Using the normal distribution, it is found that:

  • There is a 0.1292 = 12.92% probability that an individual large-cap domestic stock fund had a three-year return of at least 20%.
  • There is a 0.1587 = 15.87% probability that an individual large-cap domestic stock fund had a three-year return of 10% or less.
  • To be in the top 10%, the return has to be of at least 20.72%.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is given by the following rule:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • The z-score measures how many standard deviations the measure X is above or below the mean, depending if the z-score is positive or negative.
  • From the z-score table, the p-value associated with the z-score is found, and it represents the percentile of the measure X.

In the context of this problem, the mean and the standard deviation are given as follows:

[tex]\mu = 14.7, \sigma = 4.7[/tex]

For a return of at least 20%, the probability is one subtracted by the p-value of Z when X = 20, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (20 - 14.7)/4.7

Z = 1.13

Z = 1.13 has a p-value of 0.8708

1 - 0.8708 = 0.1292.

For the return of 10% or less, the probability is the p-value of Z when X = 10, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (10 - 14.7)/4.7

Z = -1

Z = -1 has a p-value of 0.1587.

To be in the top 10%, the return has to be of at least the 90th percentile, which is X when Z = 1.28, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

1.28 = (X - 14.7)/4.7

X - 14.7 = 1.28 x 4.7

X = 20.72%.

More can be learned about the normal distribution at https://brainly.com/question/4079902

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