Givens.
• The diameter of the semi-circle is 9.25 yd.
,
• The other two sides of the triangle are 6.83 yd and 8.66 yd long.
First, find the perimeter of the semi-circle using the circumference formula.
[tex]\begin{gathered} C_{\text{semi}}=\frac{\pi\cdot d}{2}=\frac{\pi\cdot9.25yd}{2} \\ C_{\text{semi}}\approx14.52yd \end{gathered}[/tex]
Second, add the two sides of the triangle to the circumference of the semi-circle.
[tex]\begin{gathered} P=14.52yd+6.83yd+8.66yd \\ P=30yd \end{gathered}[/tex]
Therefore, the perimeter of the figure is 30 yards.
