Respuesta :

Given

[tex]f(x)=3x^2+1,g(x)=2x-3,h(x)=x[/tex]

Answer

[tex]\begin{gathered} f(g(x))=f(2x-3) \\ =3(2x-3)^2+1 \\ =3(4x^2+9-12x)+1 \\ =12x^2+18-36x+1 \\ =12x^2-36x+19 \end{gathered}[/tex]