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The balanced equation for the reaction is:

2NO(g) + 5H2(g) ==> 2NH3(g) + 2H2O(g) 

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The balanced chemical equation is as follows:

[tex]\boxed{{\text{2NO}}\left({\text{g}}\right)+5{{\text{H}}_{\text{2}}}\left({\text{g}} \right) \to 2{\text{N}}{{\text{H}}_{\text{3}}}\left({\text{g}} \right) + 2{{\text{H}}_{\text{2}}}{\text{O}}\left( {\text{g}} \right)}[/tex]

Further explanation:

The chemical reaction that contains an equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

The steps to balance a chemical reaction are as follows:

Step1: Complete the reaction and write the unbalanced symbol equation.

Here [tex]{\text{NO}[/tex] reacts with [tex]{\text{H}_{2}[/tex] to form [tex]{\text{NH}_{3}[/tex] and [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex]. The physical state of all the reactants and products is gaseous. The unbalanced chemical equation is as follows:

 [tex]{\text{NO}}\left( {\text{g}}\right)+{{\text{H}}_{\text{2}}}\left( {\text{g}} \right) \to {\text{N}}{{\text{H}}_{\text{3}}}\left( {\text{g}}\right) + {{\text{H}}_{\text{2}}}{\text{O}}\left( {\text{g}} \right)[/tex]

Step2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

• On reactant side,

Number of nitrogen atoms is 1.

Number of hydrogen atoms is 2.

Number of oxygen atoms is 1.

• On product side,

Number of nitrogen atoms is 1.

Number of hydrogen atoms is 5.

Number of oxygen atoms is 1.

Step3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on either side, so here we balance first the number of nitrogen atoms on either side but here the number of nitrogen is one on both the sides so it is already balanced.

Step4: After this, we balance the number of hydrogen followed by oxygen.

To balance the number of atoms we have to multiply [tex]{{\text{H}}_2}[/tex]  by [tex]\dfrac{5}{2}[/tex] and number of oxygen is equal on both sides. This gives,

 [tex]{\text{NO}}\left({\text{g}} \right)+\boxed{\frac{5}{2}}{{\text{H}}_{\text{2}}}\left( {\text{g}} \right) \to{\text{N}}{{\text{H}}_{\text{3}}}\left( {\text{g}} \right) + {{\text{H}}_{\text{2}}}{\text{O}}\left( {\text{g}} \right)[/tex]

Step5: Finally, we check if all the coefficients are in whole numbers.

To convert the coefficient into the whole number, we multiply the balanced equation by 2.

[tex]\boxed{\text{2}}{\text{NO}}\left( {\text{g}} \right)+\boxed5{{\text{H}}_{\text{2}}}\left( {\text{g}} \right) \to\boxed2{\text{N}}{{\text{H}}_{\text{3}}}\left( {\text{g}} \right) + \boxed2{{\text{H}}_{\text{2}}}{\text{O}}\left( {\text{g}} \right)[/tex]  

Step 6: So, the balanced chemical equation is given as follows:

 [tex]{\text{2NO}}\left( {\text{g}} \right)+5{{\text{H}}_{\text{2}}}\left( {\text{g}}\right) \to 2{\text{N}}{{\text{H}}_{\text{3}}}\left( {\text{g}} \right) + 2{{\text{H}}_{\text{2}}}{\text{O}}\left( {\text{g}} \right)[/tex]

Learn more:

1. Determine the balanced equation: https://brainly.com/question/2612756

2. The balanced equation for ionic reaction between HI and RbOH: https://brainly.com/question/9061741

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Redox reaction

Keywords: balanced equation, 2NO, H2, 2NH3, 2H2O, nitric acid, hydrogen atom, ammonia gas, and water molecule.