[tex] \sqrt{x+6} =x-6[/tex]
[tex]x+6=(x-6)^2
[/tex]
[tex]x+6=x^2-12x+36
[/tex]
Subtract [tex]x^2-12x+36
[/tex] from both sides:
[tex]x+6-(x^2-12x+36)=x^2-12x+36-(x^2-12x+36)[/tex]
[tex]-x^2+13x-30=0
[/tex]
[tex](-x+3)(x-10)=0[/tex]
[tex]-x+3=0[/tex] or [tex]x-10=0[/tex]
Plug 3 into the equation:
[tex] \sqrt{3+6}=3-6[/tex]
[tex]3 \neq -3[/tex]
Plug 10 into your equation:
[tex] \sqrt{10+6} =10-6[/tex]
[tex]4=4[/tex]
So, your answer is:
[tex]10[/tex]
Good luck with your studies, I hope this helps!~
