A small class has
10
students,
6
of whom are girls and
4
of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a boy and the second will be a girl? Write your answer as a fraction in simplest form.

For the selection of the first student, there are 10 students, 4 of which are boys. So there is a 4/10 = 2/5 probability that the first student chosen is a boy.

Now, for the second student. There are 9 students, of which 6 are girls. So there is a 6/9 = 2/3 probability that the second will be a girl when the first was a boy.

So

[tex]P = \frac{2}{5}*\frac{2}{3} = \frac{4}{15}[/tex]

A small class has 10 students, 6 of whom are girls and 4 of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a boy and the second will be a girl? Write your answer as a fraction in simplest form.

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A small class has
10
students,
6
of whom are girls and
4
of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a boy and the second will be a girl? Write your answer as a fraction in simplest form.