Respuesta :
d/dx * sqrt(x) * sin(x) = [tex]d/dx \sqrt{x}*sin(x) + d/dx*sin(x) \sqrt{x}
[/tex]
= [tex] \frac{1}{2 \sqrt{x}} * sin(x) + cos(x)* \sqrt{x} [/tex]
=[tex] \frac{sin(x)+2xcos(x)}{2 \sqrt{x}} [/tex]
= [tex] \frac{1}{2 \sqrt{x}} * sin(x) + cos(x)* \sqrt{x} [/tex]
=[tex] \frac{sin(x)+2xcos(x)}{2 \sqrt{x}} [/tex]
You are finding the derivative of the square root of a product:
y = sqrt ( x * sin x ) = ( x * sin x )^(1/2) This is a power function!
Apply the Power Rule with Chain Rule. This involves two main steps:
1. Find the derivative of ( x * sin x)^(1/2) with respect to (x * sin x). This is
(1/2) (x * sin x)^(-1/2).
2. Multiply this result by the derivative of x * sin x (which is a PRODUCT).
Can you finish this? Hint: You must now apply the product rule.
y = sqrt ( x * sin x ) = ( x * sin x )^(1/2) This is a power function!
Apply the Power Rule with Chain Rule. This involves two main steps:
1. Find the derivative of ( x * sin x)^(1/2) with respect to (x * sin x). This is
(1/2) (x * sin x)^(-1/2).
2. Multiply this result by the derivative of x * sin x (which is a PRODUCT).
Can you finish this? Hint: You must now apply the product rule.