Respuesta :

Setor9
x^2-36
[(x)^2-(6)^2]
= (x+6)(x-6)

Answer:

The factored form of given polynomial [tex]x^2-36[/tex] is [tex](x+6)(x-6)[/tex]

Step-by-step explanation:

Given : [tex]x^2-36[/tex]

We have to factorize the given polynomial completely.

Consider the given polynomial [tex]x^2-36[/tex]

Algebraic identity[tex](a^2-b^2)=(a+b)(a-b)[/tex]

Also 36 can be written as [tex]6^2[/tex]

Thus, [tex]x^2-36[/tex] is same as [tex]x^2-6^2[/tex]

Apply the identity stated above , we have,

[tex]x^2-6^2=(x+6)(x-6)[/tex]

Thus, the factored form of given polynomial [tex]x^2-36[/tex] is [tex](x+6)(x-6)[/tex]