jeffreyrodewald
contestada

a certain car is capable of accelerating at a rate of 0.60 m/s^2. How long does it take for this car to go from a speed of 55mi/h to a speed of 60 mi/h?

I know the answer is 3.7seconds! I am just confused on the steps to get the answer.

Respuesta :

johanrusli

This car needs 3.7 seconds to go from a speed of 55 mi/h to a speed of 60 mi/h.

Further explanation

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

Given:

Acceleration = a = 0.60 m/s²

Initial Velocity = u = 55 mi/h = 24,5872 m/s

Final Velocity = v = 60 mi/h = 26,8224 m/s

Unknown:

Time Taken = t = ?

Solution:

Recall the formula for calculating acceleration as mentioned above.

[tex]a = \frac{v - u }{t}[/tex]

[tex]t = \frac{v - u }{a}[/tex]

[tex]t = \frac{26.8224 - 24.5872}{0.6}[/tex]

[tex]t = \frac{2.2352}{0.6}[/tex]

[tex]t \approx 3.7 ~ seconds[/tex]

Learn more

  • Velocity of Runner : https://brainly.com/question/3813437
  • Kinetic Energy : https://brainly.com/question/692781
  • Acceleration : https://brainly.com/question/2283922
  • The Speed of Car : https://brainly.com/question/568302

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

Ver imagen johanrusli

The time takes 3.72 seconds for this car to go from a speed of 55mi/h to a speed of 60 mi/h.

Explanation:

Given that,

Acceleration of the car [tex]a= 0.60 m/s^2[/tex]

Initial speed of the car [tex]u= 55 mi/h = 55\times 0.44704 = 24.59 m/s[/tex]

Final speed of the car [tex]v= 60 mi/h = 60\times0.44704 = 26.82 m/s[/tex]

We need to calculate the time for this car to go from a speed of 55mi/h to a speed of 60 mi/h

Using the first kinematics equation

[tex]v=u+at[/tex]

Where,

v = final speed

u = initial speed

a = acceleration

t = time

Put the value into the formula

[tex]26.82=24.59+0.60\times t[/tex]

[tex]t=\dfrac{26.82-24.59}{0.60}[/tex]

[tex]t=3.72 s[/tex]

Hence, The time takes 3.72 seconds for this car to go from a speed of 55mi/h to a speed of 60 mi/h.

Reference :

https://brainly.com/question/18329112

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