erattee
contestada

Two equations are given below:
a - 3b = 16
a = b - 2
What is the solution to the set of problems in the form (a, b)?
a. (-2, -6)
b. (-7, -9)
c. (-11, -9)
d. (-12, -10)

Respuesta :

AISstudent
You can solve this question by equating the two linear systems (by "substitution" or "elimination")

By substitution
-Take Equation 2 and substitute it in Equation 1
you will have (b-2) - 3b= 16 => -2b=18 => b=-9
-Then, take b=-9 and substitute it in one of the equations( it doesn't really matter )
For eg substituting in equation 2 yields a=-11

Final ans: C where (a,b) is (-11,-9)

The solution of the given set in the form (a, b) is (-11, -9).

What is system of equations?

The system of equations can be solved by using substitution method

The given equations are

[tex]a-3b=16\\a=b-2[/tex]

On substituting the value of a in equation [tex]1[/tex] we get,

⇒[tex](b-2)-3b=16[/tex]

⇒[tex]-2b=16+2[/tex]

⇒[tex]-2b=18[/tex]

⇒[tex]b=-9[/tex]

On substituting the value of [tex]b[/tex] in [tex]a[/tex],

[tex]a=-9-2\\[/tex]

⇒[tex]a=-11[/tex]

Hence, option (C) is correct.

Learn more about system of equations here

https://brainly.com/question/24496050

#SPJ2

Otras preguntas