Respuesta :

Work done = Force x displacement = 30 x 0.2 = 6J.

Power = Work done                  6
              -------------------   =     --------       =     3 W.
                    time                        2

Hope this helps!
nuhulawal20

The power required to lift the chair is 3 Watts.

Given the data in the question;

  • Weight of chair; [tex]w = 30N[/tex]
  • Height; [tex]0.20m[/tex]
  • Time; [tex]t = 2.0s[/tex]

Power; [tex]P =\ ?[/tex]

Power is simply the amount of energy transferred per unit time. It is expressed as:

[tex]P = \frac{W}{\delta t}[/tex]

Where W is work done and t is elapsed time.

First we determine the work done

[tex]Work\ done = Force * displacement\\\\ Work\ done = mg * h\\\\Work\ done = Weight * h\\\\Work\ done = 30N * 0.20m\\\\Work\ done = 30kg.m/s^2\ *\ 0.2m\\\\Work\ done = 6kg.m^2/s^2[/tex]

So we substitute our given values

[tex]Power = \frac{Work\ done}{\delta t} \\\\Power = \frac{6kg,m^2/s^2}{2s} \\\\Power = 3kg.m^2/s^3\\\\Power = 3J/s\\\\Power = 3Watt[/tex]

Therefore, the power required to lift the chair is 3 Watts.

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