The acceleration when he gets to the top is -0.0325 m/s²
Calculating acceleration
From the question, we are to determine the acceleration when Jacob gets to the top
Using one of the equations of motion, we have that
v = u + at
Where v is the final velocity
u is the initial velocity
a is the acceleration
and t is the time
From the given information,
u = 15 mph = 6.7 m/s
v = 3 mph = 1.34 m/s
t = 2.75 minutes = 165 seconds
Then,
1.34 = 6.7 + a×165
1.34 - 6.7 = 165a
-5.36 = 165a
a = -5.36/165
a = -0.0325 m/s²
NOTE: Negative sign indicates deceleration
Hence, the acceleration when he gets to the top is -0.0325 m/s².
Learn more on Calculating acceleration here: https://brainly.com/question/26270116
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