With 63.4° east of north, we are about 2.24 km from the starting site.
There are numerous quantities that are vectors in physics. The best feature of a vector is that it has more than one dimension.
There are so many uses for the vectors, including navigation. The airplane uses vector calculus and a variety of environmental variables, like altitude, speed, etc., to navigate accurately.
Given;
x = 2 km (Displacement in x direction)
y = 1 km (Displacement in y direction)
a) The Pythagorean theorem can be used to determine the cross-country skier's subsequent displacement:
d = [tex]\sqrt{x^{2} +y^{2} }[/tex]
d = [tex]\sqrt{2^{2}+1^{2} }[/tex]
d = [tex]\sqrt{5}[/tex]
d ≈ 2.24 km
b) The geometry of the issue allows us to determine the direction of the displacement vector:
∅ = tan⁻¹ (x/y)
∅ = tan⁻¹(2/1)
∅ ≈ 63.2⁰
With 63.4° east of north, we are about 2.24 km from the starting site.
Learn more about the displacement with the help of the given link:
https://brainly.com/question/24822049
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