Respuesta :
95.6g I2 is produced by 2*150*95.6/254 g NaI = 112.91g of NaI.(sodium iodide)
What is sodium iodide?
A metal iodide salt with a Na (+) counterion is sodium iodide. It is an iodide salt and an inorganic sodium salt. A water-soluble ionic compound having a crystal lattice is sodium iodide. Although it can be used as a supplement for complete parenteral nutrition, sodium iodide is more frequently applied in veterinary medicine.
2*150 grams of Sodium Iodide NaI must be used to produce 254 g of Iodine I₂
For the formation of Iodine from NaI , the reaction is the follows:
2NaI(aq) + Cl₂ → I₂ + 2 NaCl
To calculate how many grams of NaI are needed to produce 95.6 g of Iodine, we use a conversion factor to go backward from grams of iodine to grams of sodium iodide.
Thus, 254g I2 is produced by 2*150 g NaI
95.6g I2 is produced by 2*150*95.6/254 g NaI = 112.91g of NaI.
To learn more about sodium iodide from the given link below,
https://brainly.com/question/13897399
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