Respuesta :

91m/s^2

The initial speed of the stone vi = 10m/s

the time taken to the cliff t = 4.3s

we will use gravity , g = 9.8 m/s^2

we will use kinematic equation to solve

therefore the height of the cliff

height = gt^2/2

h = 1/2 gt^2 =

1/2 (9.8)(4.3)^2

= 90.6

= 91m/s^2

  • There are four kinematic equation, we generally use
  • vf is final velocity, vi is initially velocity, a is accelaration, Δx is displacement, t is time ,

Vf = Vi + a*t

∆x = Vi*t + 1/2a*t²

Vf² = Vi² + 2a*∆x

∆x = 1/2 (Vi + Vf)*t

To know more about  kinematic equation   visit : https://brainly.com/question/24458315

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