Respuesta :

The equation of the circle x^2 + (y + 1)^2 = 5 has a radius of √5 and a center located at (0 , -1).

The standard form of the equation of  circle is given by

(x - h)^2 + (y - k)^2 = r^2

where (h , k) is the location of the center and r is the radius of the circle.

On the other hand, the general form of the equation of  circle is given by

x^2 + y^2 + Dx + Ey + F = 0

where D = -2h, E = -2k, and F = h^2 + k^2 -r^2.

If the equation of the circle, x^2 + (y + 1)^2 = 5, is in standard form, then

h = 0

k = -1

r = √5

Learn more about equation of a circle here: https://brainly.com/question/1559324

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