The e. coli chromosome contains 4,641,652 bp. how many turns of the double helix must be unwound during replication of the e. coli chromosome? number of turns:

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12-09-2022
Biology

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The e. coli chromosome contains 4,641,652 bp. how many turns of the double helix must be unwound during replication of the e. coli chromosome? number of turns:

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bharathparasad577 bharathparasad577 · Answer 1 · 2022-09-15T08:27:14+02:00

The complementary strands of the genome must unwind completely during DNA replication to allow the creation of a new strand on each template.

The number of helical turns equals the number of base pairs divided by the of base pairs per helical turn.
As a result, 4.64 x 106/10 = 4.64 x 105 turns must be unraveled.
E. coli has a single circular chromosome that is 4.6 megabases long and contains a single replication origin (oriC).
E. coli has a single circular 4.6-Mbp chromosome on which replication begins once per creation from a single replication origin and progresses bidirectionally, aborting in a specific replication termination region.
E. coli only have one circular chromosome, which is accompanied by a circular plasmid. Lab researchers have completely sequenced its chromosomal DNA.

Learn more about DNA here:

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