contestada

Given the exponential function f (x) and the logarithmic function g(x), which of the following statements is true?

Exponential function f of x equals negative 4 to the power of x minus 1 that decreases to the right passing through the point 0 comma negative 2 and logarithmic function g of x equals negative log in base 3 of x plus 3 decreasing from left to right passing through the point 1 comma 3

As x→∞, f (x)→∞ and g(x)→0.
As x→∞, f (x)→ –∞ and g(x)→ –∞.
As x→∞, f (x)→2 and g(x)→0.
As x→∞, f (x)→2 and g(x)→∞.

Given the exponential function f x and the logarithmic function gx which of the following statements is true Exponential function f of x equals negative 4 to th class=

Respuesta :

The correct statement regarding the end behavior of the functions is given by:

As x→∞, f (x)→∞ and g(x)→0.

What is the end behavior of a function f(x)?

It is given by the limits of f(x) as x goes to infinity.

In this problem, the function f(x), the limits are given as follows:

  • [tex]\lim_{x \rightarrow -\infty} f(x) = -1[/tex].
  • [tex]\lim_{x \rightarrow \infty} f(x) = -\infty[/tex].

For function g(x), the limit is given as follows, as it is not defined for negative values:

[tex]\lim_{x \rightarrow \infty} f(x) = 0[/tex].

Hence the correct statement is:

As x→∞, f (x)→∞ and g(x)→0.

As it considers both positive infinity and negative infinity just as infinity.

More can be learned about the end behavior of a function at https://brainly.com/question/27983072

#SPJ1

Otras preguntas