Answer:
vf=43.55m/s
Explanation:
Data:
vi=29m/s
S=22m
a=2.4 m/s^2
vf=? we are supposed to find final velocity.
we will use following equation of motion:
Formula:
[tex]2as=vf^{2} -vi^{2}[/tex]
put values
[tex]2(2.4)(22)=vf^2-(29)^2\\[/tex]
solving for [tex]vf^2[/tex].
taking [tex](29)^2[/tex] on the other side .
[tex]vf^2=2(2.4)(22)+(29)^2[/tex]
solve square first.
[tex]vf^2=2(24)(22)+841[/tex]
multiply the terms.
[tex]vf^2=1056+841[/tex]
add the terms
[tex]vf^2=1897[/tex]
taking square root on both sides.
[tex]\sqrt{vf^2}=\sqrt{1897}[/tex]
square root of [tex]vf^2[/tex] will be cancelled out .
[tex]vf=43.55m/s[/tex]
