After 2 minutes an ant traveled 120 meters and after 6 minutes the ant will have traveled 260 meters.

Assuming a linear equation can be used to model the change in distance traveled over time between 2 and 6 minutes, let y be the distance traveled (in meters) after x minutes and complete this linear model in slope-intercept form:


Question 2
The significance of the slope in the context of this situation is:

The ant travels 50 meters in 35 minutes.
The ant travels at an average of 35 meters per minute.
The ant travels at an average of 50 meters per minute.
The ant travels at an average of 50 minutes per meter.
The ant travels at an average of 35 minutes per meter.

Question 3
The distance that the ant will have traveled after 14 minutes is


Question 4
The number of minutes that will pass from the time the ant begins moving until it has traveled 610 meters is

Respuesta :

1. The equation is: y = 35x + 50

2. The significance of the slope is: A. The ant travels at an average of 35 meters per minute.

3. Distance would be 490 meters.

4. Number of minutes will be: 16.

How to Model a Linear Equation?

Given that x = minutes, and y = distance, then we would have the following coordinates:

(2, 120)

(6, 260)

1. The slope (m) = change in y / change in x = 260 - 120 / 6 - 2

Slope (m) = 35

Substitute m = 35, and (x, y) = (2, 120) into y = mx + b to find b

120 = 35(2) + b

120 = 70 + b

120 - 70 = b

b = 50

Substitute m = 35 and b = 50 into y = mx + b to write the equation

y = 35x + 50

2. The slope of the graph 35.

The significance of the slope is: A. The ant travels at an average of 35 meters per minute.

3. When x = 14, we have:

y = 35(14) + 50

y = 490

Distance would be 490 meters.

4. Substitute y = 610 into y = 35x + 50

610 = 35x + 50

610 - 50 = 35x

560 = 35x

560/35 = 35x/35

16 = x

x = 16

Number of minutes will be: 16.

Learn more about linear equations on:

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