In radishes, red and white are pure-breeding colors, while hybrids are purple. If a red radish is crossed with a white radish, what will be the phenotype of the F2 generation assuming the F1 generation self- pollinates? Show the Punnett Square.

Respuesta :

The answer is 1 red radish, 2 purple radishes, and 1 white radish

Let R allele be dominant allele over r allele. The genotypes and phenotypes will be as following:
RR - red radish
rr - white radish
Rr - purple radish

Parental generation:       RR      x      rr
F1 generation:             Rr      Rr    Rr     Rr

Since the F1 generation self-pollinates, we have the situation:
F1 generation:             Rr    x    Rr
F2 generation:         RR   Rr    Rr    rr

Punnet square:
                                 Rr            
                          R      |   r
             R   
|     RR    |   Rr
Rr           r   
|     Rr      |  rr

So, there will be 1 red radish (RR), 2 purple radishes (Rr), and 1 white radish (rr)

From the Punnet square, the phenotype of the F2 generation will be 1 red radish (RR), 2 purple radishes (Rr), and 1 white radish (rr).

What is the phenotype ofthe F2 generation?

The phenotype of an organism is the physical expression of the genotype of the organism.

The dominant trait is always expressed while the recessive trait is expressed only in the absence of the dominant trait.

Assuming R allele be dominant allele over r allele.

The genotypes and phenotypes will be as follows:

RR - red radish

rr - white radish

Rr - purple radish

Parental generation:       RR      x      rr

F1 generation:             Rr      Rr    Rr     Rr

The F1 generation are all purple radish.

The F1 generation then self-pollinates:

Using a Punnet square:            

                          R      |   r

             R   |    RR    |   Rr

         r      Rr      |  rr

The F2 generation is RR,   Rr,    Rr and  rr

Therefore, the phenotype of the F2 generation will be 1 red radish (RR), 2 purple radishes (Rr), and 1 white radish (rr)

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