log(x+1) + 2logx² - 7/2log(x+1)² + 4log(x²-1)
=5log(x-1) -3log(x+1) +4logx
Logarithms are inverse functions of exponents.
logA+logB=logAB
logA-logB=(logA/logB).
In the given question
log(x+1) + 2logx² - 7/2log(x+1)² + 4log(x²-1)
=log(x-1) + 4Logx - 7log(x+1) + 4log(x+1)(x-1)
=log(x-1) + 4logx - 7log(x+1) + 4log(x+1) + 4log(x-1)
=5log(x-1) -3log(x+1) +4logx
Learn more about Logarithms here :
https://brainly.com/question/13594005
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